Matematika

Pertanyaan


[tex] \frac{lim}{x = 2} \frac{sec(x - 2) \: cos(x - 2)}{ {x}^{2} - 4x + 4} \\[/tex]
tolong disertai cara

1 Jawaban

  • lim sec(x-2).cos(x-2)/x²-4x+4
    x→2
    sec(2-2).cos(2-2)/(2)²-4(2)+4
    sec(0).cos(0)/0
    1.1/0= 1/0 = ∞

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