tolong dong nomor dua

  Diket

m air panas=3kg

m air dingin = 3 kg

T air panas= 55

T air dingin =25

c= 4200

Ditanya T campuran

Jawab

 Qlepas=Qterima

Q air panas= Q air dingin

(mxcxΔT) air panas=(mxcΔT) air dingin

3x4200(55-Tc)=3x4200(tc-25)

3(55-Tc)=3(Tc-25)

165-3Tc=3Tc-75

-3Tc-3Tc=-75-165

-6Tc=-240

Tc=-240/-6

   -400C

Catatan. 4200 air dingin dan air panas coret ya