Tolong bantu jawab pertanyaan

f(x) = x²-3x+5
g(x) = x²+2x-8

maka, f(3) = (3)²-3(3)+5 = 9-9+5 = 5

(gof) (x) = g(f(x)) = (x²-3x+5)²+2(x²-3x+5)-8
= (x²-3x+5)(x²-3x+5) + 2x²-6x+10-8
= x4-3x³+5x²-3x³+9x²-15x+5x²-15x+25+2x²-6x+2
= x4-6x³+21x²-36x+27

maka (gof) (3) = (3)^4 -6(3)³ +21(3)²-36(3)+27
= 81-162+189-108+27
= 27