Matematika

Pertanyaan

berapakah jumlah dua belas suku pertama deret aritmetika berikut a.-5+(-2)+1+...
b.6+1+(-4)+...
c.32+16+8+...

1 Jawaban

  • A. -5 + (-2) + 1 + ...
    a = -5 dan b = 3
    Sn = 1/2n [2a + (n-1)b]
    S11 = 1/2(11) [2(-5) + 10(3)]
    S11 = 11/2 (-10 + 30)
    S11 = 11/2 (20)
    S11 = 11(10)
    S11 = 110

    B. 6 + 1 + (-4) + ...
    a = 6 dan b = -5
    Sn = 1/2n [2a + (n-1)b]
    S11 = 1/2(11) [2(6) + 10(-5)]
    S11 = 11/2 (12 - 50)
    S11 = 11/2 (-38)
    S11 = 11(-19)
    S11 = -209

    C. 32 + 16 + 8 + ...
    a = 32 dan b = -16
    Sn = 1/2n [2a + (n-1)b]
    S11 = 1/2(11) [2(32) + 10(-16)]
    S11 = 11/2 (64 - 160)
    S11 = 11/2 (-96)
    S11 = 11(-48)
    S11 = -528

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