Titik titik stationer dari fungsi f(x) x3+6x2-15x+2

jawab

f(x)= x^3 + 6x^2 -15x  + 2
f' (x) = 0
3x^2 + 12x - 15 =0
x^2 + 4x - 5 = 0
(x + 5)(x -1) = 0
x = - 5  atau x = 1

f(-5) = (-5)^3 +6(-5)^2 -15(-2) +2
f(-5) = -125 + 150  + 30 +2
f(-5) = 57

f(1) = 1 + 6 -15 + 2 = -6

titik stationer (1, -6), (-5, 57)