Gunakan strategi substitusi, untuk menghitung: A) f(-1),jika f(y) = 2x^4 - y² - 3y + 6 B) f(x-1),jika f(z) = 2z^3 - z² - 3z + 6 C) f(x-2, y), jika f(x,y) = 2x^3

[tex]f( - 1) = 2 { ( - 1)}^{4} - ( - 1) {}^{2} - 3( - 1) + 6 \\ = 2 - 1 + 3 + 6 = 10 \\ f(x - 1) = 2(x - 1) {}^{3} - { (x - 1)}^{2} - 3(x - 1) + 6 \\ = 2( {x}^{2} - 2x + 1)(x - 1) - {x}^{2} + 2x - 1 - 3x + 3 + 6 \\ = 2( {x}^{3} - 3x {}^{2} + 3x - 1) - {x}^{2} + 5x + 8 = 0 \\ =2x {}^{3} - 6x {}^{2} + 6x - 2 - {x}^{2} + 5x + 8 \\ = x {}^{3} - {7x}^{2} + 11x + 6 = 0[/tex]
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