Jika garis lurus a // b, persamaan garis b adalah a. 3x + 4y + 18 = 0 b. 3x + 4y – 18 = 0 c. 4x + 3y + 12 = 0 d. 4x + 3y – 12 = 0 pake cara ya

garis a (-4,0)(0,-3)
y-y1/y2-y1 = x-x1/x2-x1
y-0/-3-0 = x+4/0+4
-3x -12 = 4y
-3x -4y = 12
-4y= 3x + 12
y= -3/4x - 3
maka ma =-3/4
karna sejajar maka ma=mb= -3/4

garis b melalui (2,3) dan mb= -3/4
y-y1 = m(x-x1)
y-3 = -3/4(x-2)
4y-12 = -3x + 6
3x + 4y - 18 =0