Tentukan konsentrasi ion OH- dan pH larutan tertentu yang mengandung 10 pangkat -5 M ion H+?

[H+] = 10^-5 M

[H+] × [OH-] = 10^-14
[OH-] = 10^-14/[H+]
[OH-] = 10^-14/ 10^-5
[OH-] = 10^-9 M

pH = -log [H+]
pH = -log (10^-5)
pH = 5

Semoga membantu ^^