Matematika

Pertanyaan

Turunan fungsi f(x)=(x²+4x)(x²-x)(x²+4)

1 Jawaban

  • f(x) = (x²+4x)(x²-x)(x²+4)
          = x^6+3x^5+8x^4+12x^3+16x²
    f'(x)= 6x^5+15x^4+32x^3+36x²+32x

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