1.Diketahui dua buah fungsi f(x)=x pangkat 2+8 dan g(x)=x-2 nilai dari (f o g) adalah 2. Diberikan duah buah fungsi f(x){ 3x pangkat2+4x+1 dan g(x)=6x nilai dar

1. f(x) = x²+8, g(x) = x-2
(fog)(x) = f(g(x)) = g(x)²+8 = (x-2)²+8 = x²-4x+4+8 = x²-4x+12

2. f(x) = 3x²+4x+1, g(x) = 6x
(fog)(x) = f(g(x)) = 3(g(x))²+4g(x)+1 = 3(6x)²+4 x 6x +1 = 3 x 36x²+24x+1 = 108x²+24x+1

3. f(x) = 2x-1, g(x) = x+5
(fog)(x) = f(g(x)) = 2g(x)-1 = 2(x+5)-1 = 2x+10-1 = 2x+9
(fog)(x) = -15
2x+9 = -15
2x = -15-9
2x = -24
x = -24/2 = -12

4. f(x) = 2x²+1, g(x) = 4x+5
(fog)(x) = f(g(x)) = 2(g(x))²+1 = 2(4x+5)²+1 = 2(16x²+40x+25)+1 = 32x²+80x+50+1 = 32x²+80x+51