tolong dibantu ya beserta caranya no 8,yg f 8/105

[tex]f) \: log_{6}( \frac{4}{15} \times \frac{32}{7} \times \frac{9}{4}) - log_{6}( \frac{8}{105} ) = log_{6}( \frac{32 \times 9 \times 105}{15 \times 7 \times 8} ) = \\ log_{6}( \frac{36 \times 21 \times 5}{5 \times 21} ) = log_{6}( {6}^{2} ) = 2[/tex]