Akar akar persamaan kuadrat x^2 -3x + 2m - 3 = 0 adalah x1 dan x2. Jika 2x1 + 3x2 = 4, maka nilai m adalah

x² - 3x + 2m - 3 = 0

x1 + x2 = -b/a = 3
x1 . x2 = c/a = 2m - 3

2x1 + 3x2 = 4
2(x1 + x2) + x2 = 4
2 . 3 + x2 = 4
x2 = 4 - 6
x2 = -2

x1 = 3 - x2 = 3 - (-2)
x1 = 5

x1 . x2 = 2m - 3
-2 . 5 = 2m - 3
2m = -10 + 3
n = -7/2