Koordinat A(3p,1) B(-9,-8) C(1,-2) terletak pada satu garis lurus. Tentukan nilai P!

Gradien = m = (y1 - y2)/(x1 - x2)

mAB = mBC
(1 - (-8))/(3p - (-9)) = (-8 - (-2))/(-9 - 1)
9/(3p + 9) = -6/-10
9/3(p + 3) = 3/5
1/(p + 3) = 1/5
p + 3 = 5
p = 2