Matematika

Pertanyaan

Lim (x -> 6) x²-4x-12/x²-7x+6

2 Jawaban

  • Kelas 11 Matematika 
    Bab Limit

    lim (x² - 4x - 12)/(x² - 7x + 6)
    x→6

    = lim ((x - 6) (x + 2)) / ((x - 6) (x - 1))
      x→6
     
    = (6 + 2)/(6 - 1)
    = 8/5
    = 1 3/5

  • [tex]lim \: x - > 6 \: \frac{(x + 2)(x - 6)}{(x - 1)(x - 6)} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{(6 + 2)}{(6 - 1) } = \frac{8}{5} [/tex]

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