Jika f(x)=3x+7dan g(x)=6/x,x≠0,nilai (fog) (2) adalah

[tex](fog)(x) = f(g(x))[/tex]
[tex]f( \frac{6}{x} ) = 3 ( \frac{6}{x} ) + 7[/tex]
[tex](fog)(x) = \frac{18}{x} + 7[/tex]
[tex](fog)(2) = 16[/tex]