Matematika

Pertanyaan

³log(2x+1) - ³log(x-7)=2

2 Jawaban

  • ³log (2x + 1) - ³log (x - 7) = 2
    ³log (2x + 1)/(x - 7) = 2
    (2x + 1)/(x - 7) = 8
    2x + 1 = 8x - 56
    6x = 57
    x = 19/2
  • 3log (2x+1) - 3log(x-7) = 2
    3log (2x+1)/(x-7) = 3log3^2
    (2x + 1)/ (x-7) = 3^2
    (2x + 1) / (x-7) = 9
    2x + 1 = 9x -63
    64 = 7x
    x = 64/7

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