³log(2x+1) - ³log(x-7)=2
Matematika
rc7
Pertanyaan
³log(2x+1) - ³log(x-7)=2
2 Jawaban
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1. Jawaban MathSolver74
³log (2x + 1) - ³log (x - 7) = 2
³log (2x + 1)/(x - 7) = 2
(2x + 1)/(x - 7) = 8
2x + 1 = 8x - 56
6x = 57
x = 19/2 -
2. Jawaban subebe
3log (2x+1) - 3log(x-7) = 2
3log (2x+1)/(x-7) = 3log3^2
(2x + 1)/ (x-7) = 3^2
(2x + 1) / (x-7) = 9
2x + 1 = 9x -63
64 = 7x
x = 64/7