Matematika

Pertanyaan

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1 Jawaban

  • Lim(x > 0) (x sin x + tan²x)/(1-cos x)
    = Lim(x > 0) (x sin x/1-cos x + tan²x/1-cos x)
    = Lim(x > 0) (x sin x/1 - (1 - 2 sin²1/2x)) + Lim(x > 0) (tan²x/1-(1-2 sin²1/2x))
    = Lim(x > 0) (x sin x/2 sin²1/2x) + Lim(x > 0) (tan²x/2 sin²1/2x)
    = Lim(x > 0) (x/2 sin 1/2x .sin x/sin 1/2x) + Lim(x > 0) 1/2(tan x/sin 1/2x)²
    = 1/2.1/ 1/2.1/ 1/2 + 1/2.(1/ 1/2)²
    = 1/2.2.2 + 1/2.2²
    = 2 + 2 = 4