please kk bantu saya menjawab janji jadikan jawaban terbaik

a. cari AC

[tex] {ac}^{2} = {ab}^{2} + {bc}^{2} \\ {ac}^{2} = {4}^{2} + {4}^{2} = 16 + 16 = 32 \\ ac = \sqrt{32} [/tex]
untuk cari AK, harus dipasang dulu titik bantu di bawah K, misal M.
Karena JK=3, maka BM=3.
[tex]{am}^{2} = {ab}^{2} + {bm}^{2} \\ {am}^{2} = {4}^{2} + {3}^{2} = 16 + 9 = 25 \\ am = \sqrt{25} = 5[/tex]
Karena BJ=1, maka KM=1.
[tex] {ak}^{2} = {am}^{2} + {km}^{2} \\ {ak}^{2} = {5}^{2} + {1}^{2} = 25 + 1 = 26 \\ ak = \sqrt{26} [/tex]
untuk cari LG, harus dipasang titik bantu di belakang K, misalnya N.
KN = BC - JK = 4 - 3 = 1
LK = AB = 4
[tex] {ln}^{2} = {lk}^{2} + {kn}^{2} \\ {ln}^{2} = {4}^{2} + {1}^{2} = 16 + 1 = 17 \\ ln = \sqrt{17} [/tex]
GN = CG - BJ = 4 - 1 = 3
[tex] {lg}^{2} = {ln}^{2} + {gn}^{2} \\ {lg}^{2} = { \sqrt{17} }^{2} + {3}^{2} = 17 + 9 = 26 \\ lg = \sqrt{26} [/tex]
b. cari AC
[tex] {ac}^{2} = {ab}^{2} + {bc}^{2} \\ {ac}^{2} = {5}^{2} + {4}^{2} \\ {ac}^{2} = 25 + 16 = 41 \\ ac = \sqrt{41} [/tex]
FG = BC = 4
[tex] {eg}^{2} = {ef}^{2} + {fg}^{2} \\ {eg}^{2} = {4}^{2} + {4}^{2} = 16 + 16 = 32 \\ eg = \sqrt{32} [/tex]
DH = AE = 4
[tex]fh = eg = \sqrt{32} \\ {df}^{2} = {dh}^{2} + {fh}^{2} = {4}^{2} + { \sqrt{32} }^{2} \\ {df}^{2} = 16 + 32 = 48 \\ df = \sqrt{48} [/tex]
[tex]ag = df = \sqrt{48} [/tex]
cmiiw :)

Gambar 1
AB = BC = CG = 4 cm
JK = 3 cm
BJ = 1 cm

Mencari AC (Diagonal Bidang)

[tex]AC= \sqrt{AB^2+BC^2} \\ AC = \sqrt{4^2+4^2} \\AC= \sqrt{2\times4^2} \\ AC=4 \sqrt{2}\ cm [/tex]

Mencari AK (Diagonal Ruang)
IJ = AB = 4 cm

[tex]AK= \sqrt{P^2+L^2+T^2} \\ \\ AK= \sqrt{IJ^2+JK^2+BJ^2}\\ AK= \sqrt{4^2+3^2+1^2}\\ AK= \sqrt{16+9+1} \\ AK= \sqrt{26}\ cm [/tex]

Mencari LG (Diagonal Ruang)
LK = AB = 4 cm
FG = (BC - JK) = 4 - 3 = 1 cm
FK = (CG - BJ) = 4 - 1 = 3 cm

[tex]LG= \sqrt{P^2+L^2+T^2} \\ \\ LG= \sqrt{LK^2+FK^2+FG^2}\\ LG= \sqrt{4^2+3^2+1^2}\\ LG= \sqrt{16+9+1} \\ LG= \sqrt{26}\ cm[/tex]


Gambar 2
AB = 5 cm
AE = BC = EF = 4 cm

Mencari AC (Diagonal Bidang)

[tex]AC= \sqrt{AB^2+BC^2} \\ AC = \sqrt{5^2+4^2} \\AC= \sqrt{25+16} \\ AC= \sqrt{41}\ cm[/tex]

Mencari EG (Diagonal Bidang)
FG = BC = 4 cm

[tex]EG= \sqrt{EF^2+FG^2} \\ EG = \sqrt{4^2+4^2} \\EG= \sqrt{2\times4^2} \\ EG=4 \sqrt{2}\ cm[/tex]

Mencari DF = AG (Diagonal Ruang)
AD = BC = 4 cm

[tex]DF= \sqrt{P^2+L^2+T^2} \\ \\ DF= \sqrt{AD^2+EF^2+AE^2}\\ DF= \sqrt{4^2+4^2+4^2}\\ DF= \sqrt{3\times(4^2)} \\ DF= 4\sqrt{3}\ cm[/tex]

***Semoga Terbantu***