Matematika

Pertanyaan

f(x)=x^2-nx dan g(x)=3x+14 nilai yang memenuhi (fog)(-4)=(gof)(2)

1 Jawaban

  • Pertama tama, tentukan dulu (f o g)(x) dan (gof)(x).
    (fog)(x) = f(g(x)) = (3x + 14)² - n(3x + 14)
    = 9x² + 84x + 196 - 3nx - 14n
    = 9x² + (84 - 3n)x + (196 - 14n)
    (gof)(x) = g(f(x)) = 3(x² - nx) + 14 = 3x² - 3nx + 14
    (fog)(-4) = 9(-4)² + (84 - 3n)(-4) + (196 - 14n) = 144 - 336 + 12n + 196 - 14n
    = 4 - 2n
    (gof)(2) = 3(2)² - 3n(2) + 14 = 12 - 6n + 14 = 26 - 6n
    (fog)(-4) = (gof)(2)
    4 - 2n = 26 - 6n
    -2n + 6n = 26 - 4
    4n = 22
    n = 22/4 = 11/2 = 5½

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