tolong jawab ya.. caranya gimana lagi butuh banget..

Dik : P = 10 cm
l = 8 cm
t = 4 cm
mempunyai gaya = 20 N
jawab = a. luas bidang tekanan = p x l
g1 = 4 cm x 8 cm
= 32 cm²
g2 = 10 cm x 4 cm
= 40cm ²
g3 = 10 cm x 8 cm
= 80 cm²

b. besar tekanan = P = F/A
g1 >> P = 20N/0,0032 m²
= 0,064 N/m²
g2>> P = 20N/0,004m²
= 0,08 N/m²
g3>> P = 20N/0,008m²
= 0,016 N/m²

semoga membantu ^^