sin 105 derajat berapa?

[tex]sin \hspace{1 mm} 105 = sin(45 + 60) \\ = sin \hspace{1 mm} 45 . cos \hspace{1 mm} 60 + cos \hspace{1 mm} 45 . sin \hspace{1 mm} 60 \\ = \frac{1}{2} \sqrt{2} . \frac{1}{2} + \frac{1}{2} \sqrt{2} \frac{1}{2} \sqrt{3} \\ = \frac{1}{4} ( \sqrt{2} + \sqrt{6}) [/tex]