tentukan lah persamaan grafik fungsi berikut jawab napa! plis:(

a) titik balik (xe,ye) = (1,2)
memotong (x,y) = (0,1)
y = a(x -xe)² + ye
1 = a(0-1)² + 2
1 - 2 = a(1)²
-1 = a
y = a(x - xe)² + ye
y = -1(x - 1)² + 2
y = -1(x² - 2x + 1) + 2
y = -x² + 2x - 1 + 2
y = -x² + 2x + 1
b) memotong x --> (x1,y1) = (-2,0) dan (x2,y2) = (3,0)
memotong y --> (x,y) = (0,-4)
y = a(x - x1)(x - x2)
-4 = a(0-(-2))(0-3)
-4 = a(2)(-3)
-4 = a(-6)
-4/-6 = a
a = 2/3
y = 2/3(x - (-2))(x - 3)
y = 2/3(x + 2)(x - 3)
y = 2/3(x² - x - 6)
y = ⅔x² - ⅔x - 4