Please, bantu isi inii... Besok dikumpulin T_T
Matematika
sunsar76
Pertanyaan
Please, bantu isi inii... Besok dikumpulin T_T
1 Jawaban
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1. Jawaban alex422
[tex]b) \: \tan(30) = \frac{x}{2} \\ \frac{1}{ \sqrt{3} } = \frac{x}{2} \\ x = \frac{2}{3} \sqrt{3} [/tex]
[tex] \cos(30) = \frac{2}{y} \\ \frac{ \sqrt{3} }{2} = \frac{2}{y} \\ y = \frac{4}{3} \sqrt{3} [/tex]
[tex]a) \cos(45) = \frac{3}{y} \\ \frac{1}{ \sqrt{2} } = \frac{3}{y} \\ y = 3 \sqrt{2} [/tex]
[tex] \tan(45) = \frac{x}{3} \\ 1 = \frac{x}{3} \\ x = 3[/tex]
[tex]c) \: \cos(60) = \frac{x}{10} \\ \frac{1}{2} = \frac{x}{10} \\ x = 5[/tex]
[tex] \sin(60) = \frac{y}{10} \\ \frac{ \sqrt{3} }{2} = \frac{y}{10} \\y = 5 \sqrt{3} [/tex]
[tex]d) \tan(30) = x \\ \frac{1}{3} \sqrt{3} = x[/tex]
[tex] \cos(30) = \frac{1}{y} \\ \frac{ \sqrt{3} }{2} = \frac{1}{y} \\ y = \frac{2}{3} \sqrt{3} [/tex]