tolong jawab soal nomor 3 aja pakai jalan yang jelas thanks

persamaan kuadrat : x² - 3x + 4 = 0
x1 + x2 = -(-3/1) = 3
x1 . x2 = 4/1 = 4
Karena akarnya berkebalikan, maka
x1 = 1/x2
x2 = 1/x1
Persamaan kuadrat barunya :
x² - (1/x2 + 1/x1)x + (1/x2.1/x1) = 0
x² - ((x1 + x2)/x1.x2)x + (1/x1.x2) = 0
x² - (3/4)x + 1/4 = 0 (kalikan 4)
4x² - 3x + 1 = 0