Mohon bantuannya ya.. Pake cara. Kalo asal aku teport
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Emotion101
Pertanyaan
Mohon bantuannya ya..
Pake cara. Kalo asal aku teport
Pake cara. Kalo asal aku teport
1 Jawaban
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1. Jawaban AnugerahRamot
Listrik Statis
[tex] Q_A = 6 \ \mu C = 6 \times 10^{-6} C \\
Q_C = - 2 \ \mu C = -2 \times 10^{-6} C \\
r_{AB} = 2 \ cm = 2 \times 10^{-2} m \\
r_{BC} = 1 \ cm = 10^{-2} m \\
\\
a. V_{BA} = \frac{k \ Q_A}{r_{AB}} \\
V_{BA} = \frac{9 \times 10^9 \cdot 6 \times 10^{-6} } { 2 \times 10^{-2} } \\
V_{BA} = 2,7 \times 10^6 \ V
\\ \\
b. V_{BC} = \frac{k \ Q_C}{r_{BC}} \\
= \frac{9 \times 10^9 \cdot (-2 \times 10^{-6} ) } {10^{-2} } \\
V_{BA} = 1,8 \times 10^6 \ V \\ \\
c. E_{BA} = \frac{k \ Q_A}{(r_{AB})^2} \\
E_{BA} = \frac{9 \times 10^9 \cdot 6 \times 10^{-6} }{ (2 \times 10^{-2} )^2 } \\
E_{BA} = 1,35 \times 10^8 \ N/C \\
\\
E_{BC} = \frac{k \ Q_C}{(r_{AB})^2} \\
E_{BC} = \frac{9 \times 10^9 \cdot 2 \times 10^{-6} }{ (10^{-2} )^2 } \\
E_{BC} = 1,8 \times 10^8 \ N/C \\
\\
Maka : \\
E_B = E_{BC} - E_{AB} \\
= 1,8 \times 10^8 - 1,35 \times 10^8
= 4,5 \times 10^7 \ N/C [/tex]